120GB Intel 2.5" SATA3 535 Series SSD (OEM) $99 + $1 Delivery Only @ NetPlus

20

Go to Deal

Store RepStopSpending on 16/06/2015 - 16:05 netplus.com.au (186 clicks)
Last edited 16/06/2015 - 16:09 by 1 other user

HUMPMONTH

Celebrating Hump Month!

120gb Intel 535 series (new series replacing the 530) SATA 2.5" SSD at just $99. Plus $1 delivery if required. Optional insurance and surcharges applicable.

Only @ NetPlus!

Type in (dont copy & paste) Promocode: HUMPMONTH

Cheers

Related Stores

NetPlus Computers

• 

  superforever on 16/06/2015 - 16:06

  Price?

• 

  Sage on 16/06/2015 - 16:08

  +6

  doesn't really compare to the now expired Sandisk 128 GB SSD deal from a couple days ago at $61. (https://www.ozbargain.com.au/node/198395)

• 

  CVonC on 16/06/2015 - 16:52

  Sup with the Intels being so much more expensive than other brands? Like even the 850 pros. Are they enterprise quality or something?

  • 

    djevoultion on 16/06/2015 - 17:02

    +1

    The Macs of SSDs.

  • 

    bentan77 on 16/06/2015 - 17:11

    850 Pros are still consumer SSDs. The more expensive Intel SSDs would have firmwares better suited for server workloads.

  • 

    scrimshaw on 16/06/2015 - 22:48

    intels are worth the price premium. A lot more reliable than other brands.

• 

  Logical on 16/06/2015 - 17:07

  +5

  make this the 240GB model for the same price and we have a bargain worthy of OzB.

  • 

    TilacVIP on 16/06/2015 - 20:20

    Would be great I'd grab one for sure, but think its pushing just a tad!!

    As for a 120GB, no deal~!!!

    • 

      Logical on 16/06/2015 - 20:29

      wouldn't be pushing too much though as I bought 2 x 240GB Crucial M500's SSD's for around $106 each (with post) some time ago.

      • 

        CVonC on 16/06/2015 - 20:33

        The amazon deal? But yeah those are consumer grade ssds

      • 

        Logical on 16/06/2015 - 20:37

        @CVonV: I thought we are all consumers ;-) They haven't skipped a beat. Run perfect in desktop and notebook. They were good value for $.